SCE–Qiyas Engineering Fundamentals – Industrial: free practice test

Practice question Unit: Engineering Economics

1. A36,000 $

   36000 is the undiscounted sum of twelve payments.

2. B22,608 $ ✓ Correct answer

   P = 3000[1−(1.08)⁻¹²]/0.08 ≈ 22608.

3. C21,417 $

   21417 does not use the stated 12-year, 8% annuity factor.

4. D56,931 $

   56931 is approximately future worth, not present worth.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Engineering Economics – IE-T1-01..03 Fundamentals, cost types, depreciation, worth analysis & discounted cash flows

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Practice question Unit: Engineering Economics

1. A3,750 units/yr

   3750 does not equate the two total-cost functions.

2. B10,000 units/yr ✓ Correct answer

   (50000−20000)/(8−5) = 10000 units per year.

3. C2,500 units/yr

   2500 is below the cost crossover point.

4. D5,385 units/yr

   5385 does not satisfy 20000+8Q = 50000+5Q.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Engineering Economics – IE-T1-04..05 Alternatives, replacement, payback, breakeven, taxes, inflation, risk

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Practice question Unit: Probability and Statistics

1. A56.0

   56 is C(8,3), which ignores award order.

2. B336 ✓ Correct answer

   8×7×6 = 336 ordered awards, with no repeat winner.

3. C24.0

   24 multiplies 8 by 3 instead of counting successive choices.

4. D512

   512 = 8³ permits the same contestant to win repeatedly.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Probability and Statistics – IE-T2-01..02 Probability, distributions, descriptive statistics, estimation, CIs

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Practice question Unit: Probability and Statistics

1. A0.800

   0.800 does not include all four squared deviations.

2. B1.44

   1.44 divides the test statistic by 3; that is not χ².

3. C4.32 ✓ Correct answer

   χ² = [(−7)²+(−3)²+5²+5²]/25 = 4.32.

4. D108

   108 is the squared-deviation sum before dividing by expected counts.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Probability and Statistics – IE-T2-03..06 Hypothesis tests, ANOVA, regression, factorial designs/DOE

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Practice question Unit: Modeling and Computation

1. A30.0

   30 is attained at (0,6), but (2,6) is better.

2. B27.0

   27 is attained at (4,3), but gives lower objective value.

3. C45.0

   45 exceeds the objective at every feasible corner.

4. D36.0 ✓ Correct answer

   The best feasible corner is (2,6): Z = 3×2+5×6 = 36.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Modeling and Computation – IE-T3-01,03,04 LP/IP, transportation, dynamic programming, sensitivity, MST/shortest path/max flow

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Practice question Unit: Industrial Management

1. A11.0 days

   11 follows A–D–E but overlooks D also waiting for B.

2. B10.0 days

   10 cannot satisfy the full B–D–E dependency chain.

3. C12.0 days ✓ Correct answer

   B finishes at day 4; D ends at 9; E ends at 12.

4. D17.0 days

   17 sums all durations and ignores parallel activities A and B.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Industrial Management – IE-T4-02 Project management: CPM, PERT, crashing, cost/time control

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Practice question Unit: Manufacturing and Production Systems

1. A3.00 ✓ Correct answer

   The theoretical lower bound is ceil((4+3+5+2+6+4)/8) = 3.

2. B2.00

   Two stations provide only 16 minutes, less than 24 required.

3. C6.00

   Six is the task count, not the theoretical minimum stations.

4. D4.00

   Four may be needed under some precedence rules, but the theoretical bound is 3.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Manufacturing and Production Systems – IE-T5-01..03,05..07 Materials & processes, integrated/lean/cellular systems, automation, CNC/robotics, DFM, line balancing

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Practice question Unit: Facilities and Logistics

1. A60.0

   60 is the sum of flows without distance weighting.

2. B7.00

   7 is the sum of distances without flow weighting.

3. C220

   220 counts each stated pair twice.

4. D110 ✓ Correct answer

   20×2 + 10×4 + 30×1 = 110 load-distance units per day.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Facilities and Logistics – IE-T6-01..03,06 Location factors, layout types, CAD layout, distance metrics, evaluating locations

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Practice question Unit: Human Factors, Productivity, Ergonomics, and Work Design

1. A0.330 min

   0.330 is only the added allowance, not total standard time.

2. B2.59 min

   2.59 uses 2.2/(1−0.15), treating allowance as a fraction of standard time.

3. C2.20 min

   2.20 omits the allowance entirely.

4. D2.53 min ✓ Correct answer

   ST = NT(1+a) = 2.2×1.15 = 2.53 minutes.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Human Factors, Productivity, Ergonomics, and Work Design – IE-T7-02 Work measurement: time study, work sampling, standards, learning curves

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Practice question Unit: Quality Engineering

1. A52.3 ✓ Correct answer

   UCL = 50 + 0.577×4 = 52.308 ≈ 52.3.

2. B62.0

   62 uses 3R instead of A₂R for subgroup means.

3. C54.6

   54.6 approximately applies A₂R twice.

4. D54.0

   54 uses R directly instead of the stated A₂ factor.

Reference: SCE–Qiyas Engineering Fundamentals – Industrial, Quality Engineering – IE-T8-04 Statistical quality control: control charts, capability, sampling

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