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KFUPM-TAHSILI

KFUPM Achievement Test (KFUPM Tahsili): free practice test

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Practice test questions with answers and explanations

Try the questions in the test above first, then open each one here to see the correct answer and why every other option is wrong.

01A red blood cell is placed in a hypertonic solution of a solute that cannot cross its membrane. Which way does water move, and what is the likely visible result?

Practice question Unit: Biology

  1. Awater enters the cell; the cell swells and may burst (haemolysis)

    Swelling and bursting happen in a hypotonic solution; here the outside is hypertonic.

  2. Bwater leaves the cell; the cell shrinks (crenation) ✓ Correct answer

    Hypertonic external medium draws water out by osmosis, so the animal cell shrinks (crenation).

  3. Cno net water movement; volume stays constant

    No net movement requires isotonic conditions; here the outside is hypertonic.

  4. Dwater leaves the cell; the membrane pulls away from the cell wall (plasmolysis)

    Water does leave, but animal cells have no cell wall, so the result is crenation, not plasmolysis.

Reference: OpenStax Biology 2e, 5.1–5.3. https://openstax.org/books/biology-2e/pages/5-chapter-summary

02A cell with 2n = 8 undergoes meiosis. How many chromosomes and chromatids does each cell contain at the end of meiosis I?

Practice question Unit: Biology

  1. A8 chromosomes, 16 chromatids

    8 chromosomes with 16 chromatids is the diploid cell after DNA replication (S phase), before meiosis I begins — not after meiosis I.

  2. B8 chromosomes, 8 chromatids

    8 chromosomes with 8 chromatids describes a diploid mitotic daughter (2n = 8, unreplicated). Meiosis I halves the chromosome number.

  3. C4 chromosomes, 4 chromatids

    4 chromosomes with 4 chromatids is the haploid product at the end of meiosis II, after sister chromatids separate.

  4. D4 chromosomes, 8 chromatids ✓ Correct answer

    In meiosis I homologues separate, so each daughter has n = 4 chromosomes; each chromosome is still made of two sister chromatids, hence 8 chromatids.

Reference: OpenStax Biology 2e, 11.1. https://openstax.org/books/biology-2e/pages/11-chapter-summary

03An ion has 26 protons, 30 neutrons and 23 electrons. Which symbol represents it correctly?

Practice question Unit: Chemistry

  1. A⁷⁹Fe³⁺

    Counted electrons in the mass number as well.

  2. B⁵⁶Fe³⁺ ✓ Correct answer

    Atomic number Z = 26 identifies iron (Fe). Mass number A = protons + neutrons = 26 + 30 = 56. Electrons 23 means three electrons fewer than protons, so the charge is 3+. Symbol: ⁵⁶Fe³⁺.

  3. C⁴⁹Fe³⁺

    Added protons and electrons to get the mass number.

  4. D⁵⁶Fe³⁻

    Charge sign reversed: losing electrons gives a positive ion.

Reference: OpenStax Chemistry 2e, 2.3–2.7: particles, isotopes, ions and nomenclature. https://openstax.org/books/chemistry-2e/pages/2-summary

04According to VSEPR theory, SO₂ has three electron domains around S (two bonding domains and one lone pair). What is the electron-domain geometry of those three domains — not the molecular shape of the atoms?

Practice question Unit: Chemistry

  1. Abent

    Bent is the molecular shape (atoms only). The stem asks for electron-domain geometry, which also counts the lone pair.

  2. Btrigonal pyramidal

    Trigonal pyramidal is the molecular shape for four domains with one lone pair (e.g. NH₃); SO₂ has three domains.

  3. Ctetrahedral

    Tetrahedral needs four electron domains.

  4. Dtrigonal planar ✓ Correct answer

    Three domains arrange as trigonal planar; the molecular shape (ignoring the lone pair’s place among the atoms) is bent.

Reference: OpenStax Chemistry 2e, Figures 7.18–7.19; molecular polarity. https://openstax.org/books/chemistry-2e/pages/7-6-molecular-structure-and-polarity

05A runner covers 400 m in 50 s, rests for 30 s, then covers another 400 m in 80 s. What is the runner’s average speed over the whole 160 s?

Practice question Unit: Physics

  1. A6.5 m/s

    Averaged the two leg speeds (8 and 5 m/s) instead of using totals.

  2. B5 m/s ✓ Correct answer

    Total distance 800 m ÷ total time 160 s = 5 m/s.

  3. C8 m/s

    That is the speed on the first leg only.

  4. D2.5 m/s

    Counts only one 400 m leg over the full 160 s (400 ÷ 160 = 2.5), forgetting the second leg.

Reference: OpenStax College Physics 2e, 2.1–2.8: displacement, vectors, speed, acceleration, kinematics and graphs. https://openstax.org/books/college-physics-2e/pages/2-section-summary

06A horizontal 10 N force pulls a 2 kg box 4 m across a frictionless floor, starting from rest. What are the work done and the box’s final kinetic energy?

Practice question Unit: Physics

  1. A40 J and 20 J

    Work is correctly 40 J (W = F s), but there is no reason to halve the kinetic energy: with no friction, all of the work becomes KE, so both are 40 J.

  2. B40 J and 40 J ✓ Correct answer

    W = F s = 10 N × 4 m = 40 J. By the work–energy theorem on a frictionless floor, ΔKE = W = 40 J (starting from rest, final KE = 40 J).

  3. C0 J and 0 J

    A frictionless floor removes friction, not the applied force; the pull does work.

  4. D20 J and 20 J

    Using ½Fs halves the work; W = Fs = 40 J.

Reference: OpenStax College Physics 2e, 7.2: net work and translational kinetic energy, equations 7.11–7.12. https://openstax.org/books/college-physics-2e/pages/7-2-kinetic-energy-and-the-work-energy-theorem

07Which expression is equal to (x + 3)(x − 3) − (x − 3)²?

Practice question Unit: Mathematics

  1. A6x

    Did not distribute the minus sign to +9: −9 + 9.

  2. B0

    Expanded (x − 3)² as x² − 9, dropping the middle term.

  3. C6x − 18 ✓ Correct answer

    (x + 3)(x − 3) = x² − 9 and (x − 3)² = x² − 6x + 9, so (x² − 9) − (x² − 6x + 9) = x² − 9 − x² + 6x − 9 = 6x − 18.

  4. D−6x − 18

    Expanded (x − 3)² as x² + 6x + 9.

Reference: OpenStax Algebra and Trigonometry 2e, Factoring, square roots, quadratic formula, discriminant and Pythagorean theorem. https://openstax.org/books/algebra-and-trigonometry-2e/pages/2-5-quadratic-equations

08Two numbers have a sum of 5, and the sum of their squares is 13. What is their product?

Practice question Unit: Mathematics

  1. A19

    Added instead of subtracting: (25 + 13)/2.

  2. B6 ✓ Correct answer

    Identity: (x + y)² = x² + y² + 2xy. With x + y = 5 and x² + y² = 13: 5² = 13 + 2xy ⇒ 25 = 13 + 2xy ⇒ 2xy = 12 ⇒ xy = 6.

  3. C−6

    Sign error when rearranging.

  4. D12

    Found 2xy and forgot to halve it.

Reference: OpenStax Algebra and Trigonometry 2e, Factoring, square roots, quadratic formula, discriminant and Pythagorean theorem. https://openstax.org/books/algebra-and-trigonometry-2e/pages/2-5-quadratic-equations

09A student surveys 20 of her friends and concludes that “everyone loves product X.” What is the main weakness of this conclusion?

Practice question Unit: Skills

  1. Athe sample is small and not representative of the wider population ✓ Correct answer

    Friends share tastes and are few; the result cannot be generalised to everyone.

  2. Bthe survey did not compare product X with competing products

    Missing a competitor comparison affects product insight, not the leap from “20 friends” to “everyone.”

  3. Cthe survey was not repeated with the same friends a week later

    Repeating it on the same group would not make the sample representative.

  4. Da margin of error was not calculated for the 20 responses

    A margin of error does not fix a convenience sample of friends; the core flaw is who was asked and how few.

Reference: Sampling, Sampling; convenience sampling; critical evaluation. https://openstax.org/books/introductory-statistics-2e/pages/1-2-data-sampling-and-variation-in-data-and-sampling

10A shop raises a price by 25%. Later it wants to bring the price back to its original value. By what percentage must it cut the new price?

Practice question Unit: Skills

  1. A20% ✓ Correct answer

    If the original is 100, the new price is 125; cutting 25 from 125 is 25/125 = 20%.

  2. B25%

    A 25% cut of 125 is 31.25, which would go below the original 100; the base has changed.

  3. C75%

    This subtracts 25% from 100%; the cut needed is 25 out of 125.

  4. D12.5%

    This halves the 25% rise; the required cut is the 25-riyal rise divided by the new price, 20%.

Reference: Percent, Percent, increase/decrease and original base. https://openstax.org/books/prealgebra-2e/pages/6-key-concepts

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