Try the questions in the test above first, then open each one here to see the correct answer and why every other option is wrong.
01The Muslim scholar who wrote «The Balance of Wisdom», contributed to the physics of motion and built several instruments is:
Past exam question Unit: Nature and History of Physics, Links to Other Sciences and the Scientific Method
AAbu al-Rayhan al-Biruni
Al-Biruni is known for determining the specific densities of several metals and stones; he did not write The Balance of Wisdom.
BAbd al-Rahman al-Khazini ✓ Correct answer
Correct. Al-Khazini wrote «The Balance of Wisdom», covering balances, density and motion.
CAl-Hasan ibn al-Haytham
Ibn al-Haytham is the author of the Book of Optics.
DAbu Bakr al-Razi
Al-Razi is known for medicine and chemistry.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.1, indicator 3, p. 8
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02Which of the following values (in newtons) cannot be the resultant of two forces of magnitudes 15\,\text{N} and 12\,\text{N}?
Past exam question Unit: Practical Work, Mathematical and Statistical Skills
A13
This value is possible since it lies between 3 and 27 and is reached at a suitable angle between the forces.
B3
This is the smallest possible value, reached when the forces point in opposite directions.
C23
This value is possible because it is less than the maximum sum of 27 and more than 3.
D30 ✓ Correct answer
Correct: the resultant ranges from 15-12 = 3\,\text{N} to 15+12 = 27\,\text{N}, so 30 lies outside this range.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.4, indicator 2, p. 9
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03Water flows steadily through a pipe made of three sections with different cross-sectional areas (A, B and C). Which statement about the mass flow rate is correct?
Past exam question Unit: Mechanics and Fluids
AThe mass flow rate is the same in all sections ✓ Correct answer
Correct: conservation of mass means the same mass passes every section each second, which is the core of the continuity equation.
BThe mass flow rate is greater at the narrowest section because the water moves faster there
The speed is higher at the narrowest section but its area is smaller, so density × area × speed stays constant.
CThe mass flow rate is greater at the widest section because its area is larger
The widest section has a larger area but slower water, so the flow rate does not increase because of it.
DThe mass flow rate decreases gradually from the first section to the last
In steady flow no mass accumulates in or leaves the pipe, so the rate does not drop along the pipe.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.6, indicator 2, p. 9; \rho A_1 v_1 = \rho A_2 v_2
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04A man pulls a crate along a smooth horizontal surface with a constant force of 5\,\text{N} directed 30^\circ above the horizontal, and the crate moves 4\,\text{m} horizontally. How much work does the force do? (\cos 30^\circ = \sqrt{3}/2)
Past exam question Unit: Mechanics and Fluids
A20\,\text{J}
This is force times distance with the angle ignored, as if the force were fully horizontal.
B10\sqrt{3}\,\text{J} ✓ Correct answer
Correct: W = F d \cos\theta = 5 \times 4 \times \frac{\sqrt{3}}{2} = 10\sqrt{3}\,\text{J}.
C10\,\text{J}
This comes from using \sin 30^\circ instead of \cos 30^\circ; the angle is measured from the horizontal, so the horizontal component needs the cosine.
D5\sqrt{3}\,\text{J}
This is half the correct value, as if the distance were 2\,\text{m} instead of 4\,\text{m}.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.5, indicator 8, p. 9; W = F d \cos\theta
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05A spring obeying Hooke's law has a spring constant of 70\,\text{N/m}. A force stretches it by 25\,\text{cm}. What is the work done on the spring, in joules, approximately?
Past exam question Unit: Heat, Properties of Matter and Thermodynamics
A4.38
This equals k x^2; the factor \frac{1}{2} was forgotten.
B17.5
This equals k x, the force at maximum stretch in newtons, not the work.
C8.75
This equals \frac{1}{2} k x; the extension was not squared.
D2.19 ✓ Correct answer
Correct: W = \frac{1}{2} k x^2 = \frac{1}{2}\times 70 \times (0.25)^2 = 2.1875 \approx 2.19\,\text{J}.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.7, indicator 1, p. 10; W = \frac{1}{2} k x^2
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06A current of 5\,\text{A} flows through a 2\,\Omega resistor for one minute. The electrical energy converted to heat in the resistor is:
Past exam question Unit: Electrostatics, Current Electricity and Magnetism
A3000\,\text{J} ✓ Correct answer
E = I^2Rt = 5^2\times2\times60 = 3000\,\text{J}.
B10\,\text{J}
This is the potential difference, IR = 10 volts, not an energy.
C50\,\text{J}
This is the power, I^2R = 50 watts, not yet multiplied by the time.
D600\,\text{J}
This is V\,t = 10\times60, missing the factor of the current.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.9, indicator 1, p. 10
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07What is the magnitude of the electric force on an electron placed in a uniform electric field of strength 500\,\text{N/C}? (electron charge 1.6\times10^{-19}\,\text{C})
Past exam question Unit: Electrostatics, Current Electricity and Magnetism
A8\times10^{-17}\,\text{N} ✓ Correct answer
F = qE = 1.6\times10^{-19}\times500 = 8\times10^{-17}\,\text{N}.
B8\times10^{-19}\,\text{N}
The power of ten is wrong: 1.6\times500=8\times10^{2}, which makes the exponent -17.
C3.2\times10^{-17}\,\text{N}
This does not follow from F = qE; 1.6\times10^{-19}\times500 is 8\times10^{-17}, not 3.2\times10^{-17}.
D3.2\times10^{-19}\,\text{N}
This is just twice the electron charge, 2\times1.6\times10^{-19}, not the product of charge and field strength.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.8, indicator 2, p. 10
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08A convex lens has a focal length of 8\,\text{cm}. Where must the object be placed in front of it to form a real image magnified four times?
Past exam question Unit: Waves and Light
A6\,\text{cm}
This object distance gives a four-times-larger image, but it is virtual and upright, not real.
B32\,\text{cm}
This is the image distance v = 4u, not the object distance.
C10\,\text{cm} ✓ Correct answer
A real image magnified four times means v = 4u, so \frac{1}{u} + \frac{1}{4u} = \frac{1}{8}, giving u = 10\,\text{cm}.
D40\,\text{cm}
At 5f = 40\,\text{cm} the image is real and diminished, near the focal point, not magnified.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.13, indicator 3, p. 11; 1/u + 1/v = 1/f
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09A proton has rest mass 1.67\times10^{-27}\,\text{kg} and moves at 80\% of the speed of light. What is its relativistic mass, approximately?
Past exam question Unit: Modern and Nuclear Physics
A2.1\times10^{-27}\,\text{kg}
This comes from using 1/0.8 instead of the correct Lorentz factor, i.e. forgetting the square root.
B1.0\times10^{-27}\,\text{kg}
This is below the rest mass, which is impossible: relativistic mass increases with speed and never decreases.
C2.8\times10^{-27}\,\text{kg} ✓ Correct answer
Correct: \gamma = \frac{1}{\sqrt{1-0.64}} = \frac{1}{0.6} = \frac{5}{3}, so m = \gamma m_0 = \frac{5}{3}\times1.67\times10^{-27} \approx 2.8\times10^{-27}\,\text{kg}.
D1.67\times10^{-27}\,\text{kg}
This is just the rest mass, meaning the effect of the high speed was ignored.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.14, indicator 1, p. 11
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10At the end of the lenses unit the teacher asks students to design a new working telescope and assemble it from lenses available in the lab. This activity belongs to the level of:
Past exam question Unit: Physics Teaching Strategies, Skills and Assessment
ASynthesis (creating) ✓ Correct answer
Correct: combining knowledge elements into a new, integrated design (a working telescope) is synthesis, one of the upper levels of Bloom's taxonomy.
BEvaluation
Evaluation requires judging the value of something against criteria, which this activity does not ask for.
CAnalysis
Analysis means breaking information into parts and finding relations between them; here students build something new rather than take it apart.
DApplication
Application means using knowledge in a familiar situation such as solving a defined problem; designing a new product from parts goes beyond that.
Reference: ETEC Physics Teacher Standards (1441 AH / 2020), specialized standard 6.6.18, indicator 2, p. 12
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