العربية

FE

Saudi Council of Engineers FE Exam: General Engineering Part: free practice test

Start with 10 free questions to see what needs more practice. Finish to see your score, weakest units and every option explained.

Back to Saudi Council of Engineers FE Exam: General Engineering Part

Practice test questions with answers and explanations

Try the questions in the test above first, then open each one here to see the correct answer and why every other option is wrong.

01A farmer fences a rectangular field on three sides only; the fourth side is an existing wall. With 80 m of fence, what is the largest possible area?

Practice question Unit: Mathematics

  1. A800 m² ✓ Correct answer

    Correct: width x and length 80-2x give A=x(80-2x); A'=80-4x=0 gives x = 20, length 40 m, so A = 800 m².

  2. B400 m²

    Assumes a 20 m × 20 m square, i.e. all four sides fenced.

  3. C1600 m²

    Takes both length and width as 40 m, which would need 120 m of fence.

  4. D600 m²

    Corresponds to 10 m × 60 m; a feasible area but not the maximum.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T1: Mathematics, indicator GE-T1-01; standard formula: التحسين بجعل المشتقة صفرًا

02Machine A makes 60% of the parts with a 2% defect rate, and machine B makes 40% with a 5% defect rate. A part is picked at random and found defective. What is the probability it came from machine B?

Practice question Unit: Probability and Statistics

  1. A0.625 ✓ Correct answer

    By Bayes' rule: 0.4 \times 0.05 / (0.6 \times 0.02 + 0.4 \times 0.05) = 0.020 / 0.032 = 0.625.

  2. B0.375

    This is the probability that the defective part came from machine A, the complement of what is asked.

  3. C0.400

    This is the prior probability of machine B and ignores the information that the part is defective.

  4. D0.032

    This is the overall probability that a part is defective (the denominator), not the probability of its source.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T2: Probability and Statistics, indicator GE-T2-02; standard formula: Bayes' rule: P(B \mid D) = P(D \mid B)P(B) / P(D)

03A 2.5 GB file is downloaded over a link with a steady throughput of 20 Mbit/s. Taking 1 GB = 1000 MB and 1 byte = 8 bits, the download time is approximately:

Practice question Unit: Computer Literacy

  1. A1000 s ✓ Correct answer

    2.5\times1000\times8 = 20000 Mbit, then 20000/20 = 1000 s.

  2. B8 s

    It comes from dividing 20 by 2.5 without converting units, which does not represent a time.

  3. C125 s

    It results from skipping the byte-to-bit conversion: 2500 MB ÷ 20 = 125 s, whereas the correct time is 8 times larger.

  4. D2500 s

    It equals the file size in megabytes and ignores the transfer rate entirely.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T3: Computer Literacy, indicator GE-T3-01; standard formula: time = size (bit) / rate (bit/s)

04A simply supported beam of span 5 m carries a uniformly distributed load of 10 kN/m over its full length plus a 20 kN point load at 2 m from support A. What is the vertical reaction at B?

Practice question Unit: Statics and Dynamics

  1. A37 kN

    This is the reaction at A (total load 70 kN minus 33 kN).

  2. B35 kN

    This is half the total load, which is wrong because the point load is not at mid-span.

  3. C25 kN

    This is the share from the distributed load alone, ignoring the point load.

  4. D33 kN ✓ Correct answer

    Moments about A: R_B \times 5 = 50 \times 2.5 + 20 \times 2 = 165, so R_B = 33 kN.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T4: Statics and Dynamics, indicator GE-T4-01

05When \mathrm{Al + HCl \rightarrow AlCl_3 + H_2} is balanced with the smallest whole numbers, what is the sum of the coefficients?

Practice question Unit: Chemistry

  1. A12

    Coefficients such as 2, 5, 2, 3 or 2, 6, 2, 2 sum to 12 but leave Cl or H unbalanced.

  2. B11

    Coefficients such as 2, 6, 2, 1 sum to 11 but leave H unbalanced (6 atoms against 2).

  3. C13 ✓ Correct answer

    Correct: \mathrm{2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2}, and 2 + 6 + 2 + 3 = 13.

  4. D15

    Coefficients such as 2, 6, 2, 5 sum to 15 but leave H unbalanced (6 atoms against 10).

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T5: Chemistry, indicator GE-T5-03

06A steel has a yield strength of 250 MPa and a modulus of elasticity of 200 GPa. What is its modulus of resilience?

Practice question Unit: Materials Science and Engineering

  1. A0.156 MJ/m³ ✓ Correct answer

    Correct: U_r=\sigma_y^2/(2E)=250^2/(2\times200000)=0.156 MJ/m³.

  2. B0.078 MJ/m³

    Wrong: this value comes from dividing by 4E instead of 2E, which is not the correct formula.

  3. C0.313 MJ/m³

    Wrong: this value omits the factor 1/2; the area under the elastic curve is a triangle, not a rectangle.

  4. D1.56 MJ/m³

    Wrong: this value is ten times too large and comes from a slip in the power of ten during unit conversion.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T8: Materials Science and Engineering, indicator GE-T8-01; standard formula: U_r=\sigma_y^2/(2E)

07A company has revenue of SAR 1,200,000, cost of goods sold of SAR 700,000, operating expenses of SAR 250,000, and loan interest of SAR 50,000. If tax is 25% of profit before tax, what is net income?

Practice question Unit: Engineering Economics

  1. ASAR 187,500

    This taxes profit before deducting interest (250,000 × 0.75); interest is deducted first and tax is computed afterward.

  2. BSAR 200,000

    This is profit before tax; the tax has not been deducted.

  3. CSAR 150,000 ✓ Correct answer

    Profit before tax = 1,200,000 − 700,000 − 250,000 − 50,000 = 200,000; tax is 50,000, so net income is SAR 150,000.

  4. DSAR 250,000

    This is profit after operating expenses but before interest and tax.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T11: Engineering Economics, indicator GE-T11-01

08A contractor works under a cost-plus-fixed-fee contract. The estimated cost is SAR 750,000, the fixed fee is 10% of the estimated cost, and the actual reimbursable cost is SAR 800,000. What total amount does the owner pay?

Practice question Unit: Project Management

  1. ASAR 880,000

    This figure applies the percentage to the actual cost, but the fee here is fixed from the estimated cost.

  2. BSAR 875,000 ✓ Correct answer

    The actual cost of 800,000 is reimbursed plus the fixed fee of 75,000 (10% of 750,000), giving 875,000.

  3. CSAR 825,000

    This figure adds the estimated cost to the fee and ignores the actual reimbursable cost.

  4. DSAR 800,000

    This figure repays only the actual cost and leaves out the contractor's fee.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T12: Project Management, indicator GE-T12-01

09After issuing construction drawings, an engineer finds a calculation error in his design that reduces the safety margin of a structural member; construction has not started. What is the most appropriate sequence of actions?

Practice question Unit: Ethics and Professionalism

  1. AWait for the next periodic project review and then correct the error if it is confirmed

    Delay raises the chance that the flawed design gets built.

  2. BCorrect the error quietly and hand over new drawings without telling any party why they changed

    Concealing it keeps affected parties unaware and breaches honesty.

  3. CNotify the owner at once, then correct the design and issue revised drawings replacing the earlier ones ✓ Correct answer

    Immediate notification, correction and withdrawal of old drawings is the transparent course that protects the public.

  4. DLeave the design as is because the margin is still positive

    A safety margin below the approved design basis cannot be accepted without everyone's knowledge.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T13: Ethics and Professionalism, indicator GE-T13-01

10An operating rule that always holds: if the cooling pump fails, the alarm sounds. The alarm did not sound during the shift. Which conclusion follows necessarily?

Practice question Unit: General Skills

  1. AThe pump failed but the alarm itself is faulty

    This contradicts the rule that the alarm always sounds when the pump fails.

  2. BThe cooling pump did not fail during the shift ✓ Correct answer

    Correct: by the contrapositive, had the pump failed the alarm would have sounded.

  3. CThe pump's state cannot be determined from this information

    It can be determined: the absence of the certain result (the alarm) rules out the cause (failure).

  4. DThe cooling pump is operating at full efficiency

    Not failing does not mean full efficiency; the pump may run poorly without failing.

Reference: SCE-Qiyas Engineering Fundamentals Exam, General Engineering Standards (2014), Topic T14: General Skills, indicator GE-T14-01

Keep preparing for Saudi Council of Engineers FE Exam: General Engineering Part

See also: Engineering Exams